32x^2-33x+1=0

Solution for 32x^2-33x+1=0 equation:

32x^2-33x+1=0

a = 32; b = -33; c = +1;
Δ = b2-4ac
Δ = -332-4·32·1
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-31}{2*32}=\frac{2}{64}
=1/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+31}{2*32}=\frac{64}{64}
=1
$